7x^2+57x+10=2

Solution for 7x^2+57x+10=2 equation:

7x^2+57x+10=2

We move all terms to the left:

7x^2+57x+10-(2)=0

We add all the numbers together, and all the variables

7x^2+57x+8=0

a = 7; b = 57; c = +8;
Δ = b2-4ac
Δ = 572-4·7·8
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-55}{2*7}=\frac{-112}{14}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+55}{2*7}=\frac{-2}{14}
=-1/7
$